60=x^2+10x

Solution for 60=x^2+10x equation:

60=x^2+10x

We move all terms to the left:

60-(x^2+10x)=0

We get rid of parentheses

-x^2-10x+60=0

We add all the numbers together, and all the variables

-1x^2-10x+60=0

a = -1; b = -10; c = +60;
Δ = b2-4ac
Δ = -102-4·(-1)·60
Δ = 340
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{340}=\sqrt{4*85}=\sqrt{4}*\sqrt{85}=2\sqrt{85}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{85}}{2*-1}=\frac{10-2\sqrt{85}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{85}}{2*-1}=\frac{10+2\sqrt{85}}{-2}
$